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x^2+25x+114=0
a = 1; b = 25; c = +114;
Δ = b2-4ac
Δ = 252-4·1·114
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-13}{2*1}=\frac{-38}{2} =-19 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+13}{2*1}=\frac{-12}{2} =-6 $
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